26x^2-99x+28=0

Solution for 26x^2-99x+28=0 equation:

26x^2-99x+28=0

a = 26; b = -99; c = +28;
Δ = b2-4ac
Δ = -992-4·26·28
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6889}=83$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-99)-83}{2*26}=\frac{16}{52}
=4/13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-99)+83}{2*26}=\frac{182}{52}
=3+1/2
$